What is the solution for y^{''}+y=3e^{-8x} ?

The solution for y^{''}+y=3e^{-8x} is y=c_{1}cos(x)+c_{2}sin(x)+3/65 e^{-8x}

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y^{''}+y=3e^{-8x}

y^{^{''}} + y = 3 e^{- 8 x}

y = c_{1} cos (x) + c_{2} sin (x) + \frac{3}{65} e^{- 8 x}

Solution steps

y^{''} (x) + y = 3 e^{- 8 x}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + \frac{3}{65} e^{- 8 x}

y = c_{1} cos (x) + c_{2} sin (x) + \frac{3}{65} e^{- 8 x}

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What is the solution for y^{''}+y=3e^{-8x} ?
The solution for y^{''}+y=3e^{-8x} is y=c_{1}cos(x)+c_{2}sin(x)+3/65 e^{-8x}