What is area f(x)= 1/(7(1+x^2)),g(x)= 1/14 x^2 ?

The answer to area f(x)= 1/(7(1+x^2)),g(x)= 1/14 x^2 is pi/(14)-1/21

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area f(x)= 1/(7(1+x^2)),g(x)= 1/14 x^2

area

f (x) = \frac{1}{7 ( 1 + x ^{2} )}, g (x) = \frac{1}{14} x^{2}

\frac{π}{14} - \frac{1}{21}

Decimal Notation

0.17678 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} \frac{1}{7 ( 1 + x ^{2} )} - \frac{1}{14} x^{2} d x

Solve

\int_{- 1}^{1} \frac{1}{7 ( 1 + x ^{2} )} - \frac{1}{14} x^{2} d x : \frac{π}{14} - \frac{1}{21}

The area is:

= \frac{π}{14} - \frac{1}{21}

\int \frac{1 + 13 x}{x} d x

x \cdot y \cdot y^{^{'}} = y^{2} + 1

\int - 18 x^{2} d x

x \to 2 - lim (\frac{x}{x - 2})

y = 5 x^{2} + 7 x - 4

What is area f(x)= 1/(7(1+x^2)),g(x)= 1/14 x^2 ?
The answer to area f(x)= 1/(7(1+x^2)),g(x)= 1/14 x^2 is pi/(14)-1/21