What is the solution for x*y*y^'=y^2+1 ?

The solution for x*y*y^'=y^2+1 is y=sqrt(c_{1)x^2-1},y=-sqrt(c_{1)x^2-1}

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xyy^'=y^2+1

x \cdot y \cdot y^{^{'}} = y^{2} + 1

y = c_{1} x^{2} - 1, y = - c_{1} x^{2} - 1

Solution steps

x \cdot y \cdot y^{'} (x) = y^{2} + 1

Solve separable ODE:

y = c_{1} x^{2} - 1, y = - c_{1} x^{2} - 1

y = c_{1} x^{2} - 1, y = - c_{1} x^{2} - 1

\int - 18 x^{2} d x

x \to 2 - lim (\frac{x}{x - 2})

y = 5 x^{2} + 7 x - 4

4^{4 x}

\frac{\partial}{\partial y} (x \cdot cos (y))

What is the solution for x*y*y^'=y^2+1 ?
The solution for x*y*y^'=y^2+1 is y=sqrt(c_{1)x^2-1},y=-sqrt(c_{1)x^2-1}