What is the derivative of 4^{4x} ?

The derivative of 4^{4x} is ln(2)*2^{8x+3}

What is the first derivative of 4^{4x} ?

The first derivative of 4^{4x} is ln(2)*2^{8x+3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

4^{4 x}

ln (2) \cdot 2^{8 x + 3}

Solution steps

\frac{d}{d x} (4^{4 x})

Simplify

4^{4 x} : 25 6^{x}

= \frac{d}{d x} (25 6^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 25 6^{x} ln (256)

Simplify

25 6^{x} ln (256) : ln (2) \cdot 2^{8 x + 3}

= ln (2) \cdot 2^{8 x + 3}

\frac{\partial}{\partial y} (x \cdot cos (y))

y = \frac{6 x}{x + 5}, (- 3, - 9)

n = - \infty \sum \infty n^{2}

\frac{x - arctan ( x )}{x ^{2}}

\int_{1}^{3} 2 x^{2} + 2 x + 4 d x

What is the derivative of 4^{4x} ?
The derivative of 4^{4x} is ln(2)*2^{8x+3}
What is the first derivative of 4^{4x} ?
The first derivative of 4^{4x} is ln(2)*2^{8x+3}