What is the tangent of y=(6x)/(x+5),(-3,-9) ?

The tangent of y=(6x)/(x+5),(-3,-9) is y= 15/2 x+27/2

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tangent of y=(6x)/(x+5),(-3,-9)

tangent of

y = \frac{6 x}{x + 5}, (- 3, - 9)

y = \frac{15}{2} x + \frac{27}{2}

Solution steps

Find the slope of

y = \frac{6 x}{x + 5} : \frac{d y}{d x} = \frac{30}{( x + 5 ) ^{2}}

Compute the slope of

y = \frac{6 x}{x + 5}

(- 3, - 9) : m = \frac{15}{2}

Find the line with slope m=

\frac{15}{2}

and passing through

(- 3, - 9) : y = \frac{15}{2} x + \frac{27}{2}

y = \frac{15}{2} x + \frac{27}{2}

n = - \infty \sum \infty n^{2}

\frac{x - arctan ( x )}{x ^{2}}

\int_{1}^{3} 2 x^{2} + 2 x + 4 d x

\int \frac{1}{cot ^{2} ( x )} d x

11 x + 2

What is the tangent of y=(6x)/(x+5),(-3,-9) ?
The tangent of y=(6x)/(x+5),(-3,-9) is y= 15/2 x+27/2