What is the integral of 1/(cot^2(x)) ?

The integral of 1/(cot^2(x)) is -x+tan(x)+C

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integral of 1/(cot^2(x))

\int \frac{1}{cot ^{2} ( x )} d x

- x + tan (x) + C

Solution steps

\int \frac{1}{cot ^{2} ( x )} d x

Rewrite using trig identities

= \int tan^{2} (x) d x

Rewrite using trig identities

= \int - 1 + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d x + \int sec^{2} (x) d x

\int 1 d x = x

\int sec^{2} (x) d x = tan (x)

= - x + tan (x)

Add a constant to the solution

= - x + tan (x) + C

11 x + 2

\frac{d}{d x} (\frac{1}{x} + x)

\int e^{3 x} (3 + 9 x) d x

3 x + 4

n = 2 \sum \infty \frac{n}{2 ^{n}}

What is the integral of 1/(cot^2(x)) ?
The integral of 1/(cot^2(x)) is -x+tan(x)+C