What is the limit as x approaches-1 of ln(1+x^3) ?

The limit as x approaches-1 of ln(1+x^3) is Does not exist

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limit as x approaches-1 of ln(1+x^3)

x \to - 1 lim (ln (1 + x^{3}))

Does not exist

Solution steps

x \to - 1 lim (ln (1 + x^{3}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (ln (1 + x^{3})) = - \infty

x \to - 1 - lim (ln (1 + x^{3})) =

Does not exist

= Does not exist

f (x) = x^{3} - 7 x + 6, at x = - 1

\int \frac{1}{( x ^{3} + x )} d x

\int \frac{x - 4}{( x + 2 ) ^{2} + 16} d x

x \to 0 lim (\frac{e ^{x^{3}} - 1}{x})

\frac{\partial}{\partial x} (2 x - 2 x y)

What is the limit as x approaches-1 of ln(1+x^3) ?
The limit as x approaches-1 of ln(1+x^3) is Does not exist