What is (\partial)/(\partial x)(2x-2xy) ?

The answer to (\partial)/(\partial x)(2x-2xy) is 2-2y

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(\partial)/(\partial x)(2x-2xy)

\frac{\partial}{\partial x} (2 x - 2 x y)

2 - 2 y

Solution steps

\frac{\partial}{\partial x} (2 x - 2 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (2 x y)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (2 x y) = 2 y

= 2 - 2 y

\int \frac{2 sin ( x )}{1} d x

f (x) = (ln (x))^{4}, at x = 7

\frac{\partial}{\partial x} (3 y^{2} - x)

\int (x^{2} + 5)^{3} d x

3 - t

What is (\partial)/(\partial x)(2x-2xy) ?
The answer to (\partial)/(\partial x)(2x-2xy) is 2-2y