What is (\partial)/(\partial x)(3y^2-x) ?

The answer to (\partial)/(\partial x)(3y^2-x) is -1

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(\partial)/(\partial x)(3y^2-x)

\frac{\partial}{\partial x} (3 y^{2} - x)

- 1

Solution steps

\frac{\partial}{\partial x} (3 y^{2} - x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 y^{2}) - \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (3 y^{2}) = 0

\frac{\partial}{\partial x} (x) = 1

= 0 - 1

Simplify

= - 1

\int (x^{2} + 5)^{3} d x

3 - t

\int cos^{2} (π x) d x

\frac{2 - x e ^{x}}{x + e ^{x}}

2 y^{^{''}} + 27 y = 0, y (0) = 6, y^{^{'}} (0) = 5

What is (\partial)/(\partial x)(3y^2-x) ?
The answer to (\partial)/(\partial x)(3y^2-x) is -1