What is the tangent of f(x)=x^2,(1,1) ?

The tangent of f(x)=x^2,(1,1) is y=2x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2,(1,1)

tangent of

f (x) = x^{2}, (1, 1)

y = 2 x - 1

Solution steps

Find the slope of

f (x) = x^{2} : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2}

(1, 1) : m = 2

Find the line with slope m=

2

and passing through

(1, 1) : y = 2 x - 1

y = 2 x - 1

\int x^{\frac{- 7}{3}} d x

\frac{d}{d x} (\frac{x ^{2} + x + 1}{x ^{2} + 3})

(15, 250), (25, 28)

\frac{d}{d x} ((2 - x + 3 x^{2}) (x^{3} + 5 e^{x}))

\int \frac{1}{2 - sin ^{2} ( x )} d x