What is (\partial)/(\partial y)(tan(2x+3y)) ?

The answer to (\partial)/(\partial y)(tan(2x+3y)) is sec^2(2x+3y)*3

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(\partial)/(\partial y)(tan(2x+3y))

\frac{\partial}{\partial y} (tan (2 x + 3 y))

sec^{2} (2 x + 3 y) \cdot 3

Solution steps

\frac{\partial}{\partial y} (tan (2 x + 3 y))

Treat

x

as a constant

Apply the chain rule:

sec^{2} (2 x + 3 y) \frac{\partial}{\partial y} (2 x + 3 y)

= sec^{2} (2 x + 3 y) \frac{\partial}{\partial y} (2 x + 3 y)

\frac{\partial}{\partial y} (2 x + 3 y) = 3

= sec^{2} (2 x + 3 y) \cdot 3

2 - 2 e^{- 4 t}

sin (t) sin (t)

\frac{\partial}{\partial x} (x^{3} - 3 x y + y^{3})

x \to - 2 lim (\frac{1}{∣ x + 2 ∣} + x^{2})

y^{^{'}} = 2.5 - \frac{y}{2000}

What is (\partial)/(\partial y)(tan(2x+3y)) ?
The answer to (\partial)/(\partial y)(tan(2x+3y)) is sec^2(2x+3y)*3