What is the integral of \sqrt[9]{r^2} ?

The integral of \sqrt[9]{r^2} is 9/11 r^{11/9}+C

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integral of \sqrt[9]{r^2}

\frac{9}{11} r^{\frac{11}{9}} + C

Solution steps

assuming

r \geq 0

= \int r^{\frac{2}{9}} d r

Apply the Power Rule

: \frac{9}{11} r^{\frac{11}{9}}

= \frac{9}{11} r^{\frac{11}{9}}

Add a constant to the solution

= \frac{9}{11} r^{\frac{11}{9}} + C

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What is the integral of \sqrt[9]{r^2} ?
The integral of \sqrt[9]{r^2} is 9/11 r^{11/9}+C