What is the limit as x approaches+0 of (1/(x^2))^2 ?

The limit as x approaches+0 of (1/(x^2))^2 is infinity

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limit as x approaches+0 of (1/(x^2))^2

x \to + 0 lim ((\frac{1}{x ^{2}})^{2})

\infty

Solution steps

x \to 0 lim ((\frac{1}{x ^{2}})^{2})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim ((\frac{1}{x ^{2}})^{2}) = \infty

x \to 0 + lim ((\frac{1}{x ^{2}})^{2}) = \infty

= \infty

n \to - \infty lim (e^{n})

n = 0 \sum \infty e^{2 n}

x \to 0 lim (\frac{6 ^{x} - 2 ^{x}}{x})

x \to 0 + lim (x^{3} ln (x))

f (x) = \frac{x}{x ^{2} + 9}

What is the limit as x approaches+0 of (1/(x^2))^2 ?
The limit as x approaches+0 of (1/(x^2))^2 is infinity