What is the solution for 2ty^'+y=e^t ?

The solution for 2ty^'+y=e^t is y=(sqrt(pi)\erfi(sqrt(t)))/(2sqrt(t))+(c_{1})/(sqrt(t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2ty^'+y=e^t

2 t y^{^{'}} + y = e^{t}

y = \frac{π erfi ( t )}{2 t} + \frac{c _{1}}{t}

Solution steps

2 t y^{'} (t) + y = e^{t}

Solve linear ODE:

y = \frac{π erfi ( t )}{2 t} + \frac{c _{1}}{t}

y = \frac{π erfi ( t )}{2 t} + \frac{c _{1}}{t}

\frac{\partial}{\partial y} (x^{2} - x - 12 y + 1)

\int_{0}^{27} \frac{4}{x ^{\frac{2}{3}}} d x

\int 5 x ln (4 x) d x

f (x) = x^{2} + 3 x - 7

\frac{\partial}{\partial s} (- 3 s^{2} + t^{2})

What is the solution for 2ty^'+y=e^t ?
The solution for 2ty^'+y=e^t is y=(sqrt(pi)\erfi(sqrt(t)))/(2sqrt(t))+(c_{1})/(sqrt(t))