What is the integral of 9arcsin(x) ?

The integral of 9arcsin(x) is 9(xarcsin(x)+sqrt(1-x^2))+C

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integral of 9arcsin(x)

\int 9 arcsin (x) d x

9 (x arcsin (x) + 1 - x^{2}) + C

Solution steps

\int 9 arcsin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int arcsin (x) d x

Apply Integration By Parts

: x arcsin (x) - \int \frac{x}{1 - x ^{2}} d x

= 9 (x arcsin (x) - \int \frac{x}{1 - x ^{2}} d x)

\int \frac{x}{1 - x ^{2}} d x = - 1 - x^{2}

= 9 (x arcsin (x) - (- 1 - x^{2}))

Simplify

= 9 (x arcsin (x) + 1 - x^{2})

Add a constant to the solution

= 9 (x arcsin (x) + 1 - x^{2}) + C

f (x) = 3 e^{3 x}

\frac{d}{d x} (x^{(\frac{4}{5})} (x - 4)^{2})

\frac{d y}{d x} = \frac{x}{4 + x ^{2}}

\frac{d}{d x} (2^{x} ln (x))

\int \frac{x ^{2}}{x ^{3} + 1} d x

What is the integral of 9arcsin(x) ?
The integral of 9arcsin(x) is 9(xarcsin(x)+sqrt(1-x^2))+C