What is the d/(dy)(e^xtan(y)) ?

The d/(dy)(e^xtan(y)) is e^xsec^2(y)

What is the first d/(dy)(e^xtan(y)) ?

The first d/(dy)(e^xtan(y)) is e^xsec^2(y)

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\frac{d}{d y} (e^{x} tan (y))

e^{x} sec^{2} (y)

Solution steps

\frac{d}{d y} (e^{x} tan (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{x} \frac{d}{d y} (tan (y))

Apply the common derivative:

\frac{d}{d y} (tan (y)) = sec^{2} (y)

= e^{x} sec^{2} (y)

\frac{d x}{d t} = t - x

\frac{d}{d x} (3 cos^{3} (x))

\int (5 x - 2)^{7} d x

5 t

\frac{\partial}{\partial y} (\frac{y}{1 + x ^{2} y ^{2}})

What is the d/(dy)(e^xtan(y)) ?
The d/(dy)(e^xtan(y)) is e^xsec^2(y)
What is the first d/(dy)(e^xtan(y)) ?
The first d/(dy)(e^xtan(y)) is e^xsec^2(y)