What is the solution for t(dy)/(dt)=t^3+4t^3y ?

The solution for t(dy)/(dt)=t^3+4t^3y is y=(e^{(4t^3+c_{1})/3})/(4)-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t(dy)/(dt)=t^3+4t^3y

t \frac{d y}{d t} = t^{3} + 4 t^{3} y

y = \frac{e ^{\frac{4 t ^{3} + c _{1}}{3}}}{4} - \frac{1}{4}

Solution steps

t \frac{d y}{d t} = t^{3} + 4 t^{3} y

Solve separable ODE:

y = \frac{e ^{\frac{4 t ^{3} + c _{1}}{3}}}{4} - \frac{1}{4}

y = \frac{e ^{\frac{4 t ^{3} + c _{1}}{3}}}{4} - \frac{1}{4}

\int (x^{2} + 3) 5 x d x

f (x) = (3 x^{3} + 2) (x^{4} - 2 x)

\frac{d y}{d x} x + y = (x y)^{\frac{3}{2}}

\int \frac{1}{1 + 8 x} d x

\frac{d}{d x} (6^{s i n (π x)})

What is the solution for t(dy)/(dt)=t^3+4t^3y ?
The solution for t(dy)/(dt)=t^3+4t^3y is y=(e^{(4t^3+c_{1})/3})/(4)-1/4