What is the derivative of x+ln(x^2+1) ?

The derivative of x+ln(x^2+1) is 1+(2x)/(x^2+1)

What is the first derivative of x+ln(x^2+1) ?

The first derivative of x+ln(x^2+1) is 1+(2x)/(x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x + ln (x^{2} + 1))

1 + \frac{2 x}{x ^{2} + 1}

Solution steps

\frac{d}{d x} (x + ln (x^{2} + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (ln (x^{2} + 1))

\frac{d x}{d x} = 1

\frac{d}{d x} (ln (x^{2} + 1)) = \frac{2 x}{x ^{2} + 1}

= 1 + \frac{2 x}{x ^{2} + 1}

y = 2 x + 2, y = x^{2} + 2, x = - 1, x = 3

x \to - π lim (\frac{sin ( x )}{x})

\frac{d}{d x} (- x^{2} + 2 x + 3)

\int 2 t + 1 d t

y = ln (1 - x^{2})

What is the derivative of x+ln(x^2+1) ?
The derivative of x+ln(x^2+1) is 1+(2x)/(x^2+1)
What is the first derivative of x+ln(x^2+1) ?
The first derivative of x+ln(x^2+1) is 1+(2x)/(x^2+1)