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Popular >

f(x)= 1/((x+1)(x+2)(x+3))

Solution

f (x) = \frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )}

Solution

Domain : x < - 3 or - 3 < x < - 2 or - 2 < x < - 1 or x > - 1

Range : f (x) < 0 or f (x) > 0

Y Intercepts : (0, \frac{1}{6})

Asymptotes : Vertical x = - 3, x = - 2, x = - 1, Horizontal y = 0

Extreme Points : Minimum (- \frac{6 + 3}{3}, \frac{3 3}{2}), Maximum (\frac{- 6 + 3}{3}, - \frac{3 3}{2})

+1

Interval Notation

Domain : (- \infty, - 3) \cup (- 3, - 2) \cup (- 2, - 1) \cup (- 1, \infty)

Range : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )} : x < - 3 or - 3 < x < - 2 or - 2 < x < - 1 or x > - 1

Range of

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )} : f (x) < 0 or f (x) > 0

Axis interception points of

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )} :

Y Intercepts

: (0, \frac{1}{6})

Asymptotes of

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )} :

Vertical

: x = - 3, x = - 2, x = - 1,

Horizontal

: y = 0

Extreme Points of

\frac{1}{( x + 1 ) ( x + 2 ) ( x + 3 )} :

Minimum

(- \frac{6 + 3}{3}, \frac{3 3}{2}),

Maximum

(\frac{- 6 + 3}{3}, - \frac{3 3}{2})

Popular Examples

f(x)=x^4-5x^3+28x-16

f (x) = x^{4} - 5 x^{3} + 28 x - 16

y = x^{6} - x^{2} - x

f(x)=sqrt((x^2+3x)/(x^2-16))

f (x) = \frac{x ^{2} + 3 x}{x ^{2} - 16}

f(x)=log_{1/5}(x^2-x-12)+6

f (x) = lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6

f(x)=(5-2x)/(4x-2)

f (x) = \frac{5 - 2 x}{4 x - 2}

Frequently Asked Questions (FAQ)

What is the f(x)= 1/((x+1)(x+2)(x+3)) ?
The f(x)= 1/((x+1)(x+2)(x+3)) is