What is the f(x)=(sqrt(x^2-9))/(x^2+2x-8) ?

The f(x)=(sqrt(x^2-9))/(x^2+2x-8) is

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f(x)=(sqrt(x^2-9))/(x^2+2x-8)

f (x) = \frac{x ^{2} - 9}{x ^{2} + 2 x - 8}

Domain : x < - 4 or - 4 < x \leq - 3 or x \geq 3

Range : - \infty < f (x) < \infty

X Intercepts : (3, 0), (- 3, 0)

Asymptotes : Vertical x = - 4, Horizontal y = 0

Extreme Points : Maximum (- 3, 0), Minimum (3, 0), Maximum (3.83346 \dots, 0.16616 \dots)

Interval Notation

Domain : (- \infty, - 4) \cup (- 4, - 3] \cup [3, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{x ^{2} - 9}{x ^{2} + 2 x - 8} : x < - 4 or - 4 < x \leq - 3 or x \geq 3

Range of

\frac{x ^{2} - 9}{x ^{2} + 2 x - 8} : - \infty < f (x) < \infty

Axis interception points of

\frac{x ^{2} - 9}{x ^{2} + 2 x - 8} :

X Intercepts

: (3, 0), (- 3, 0)

Asymptotes of

\frac{x ^{2} - 9}{x ^{2} + 2 x - 8} :

Vertical

: x = - 4,

Horizontal

: y = 0

Extreme Points of

\frac{x ^{2} - 9}{x ^{2} + 2 x - 8} :

Maximum

(- 3, 0),

Minimum

(3, 0),

Maximum

(3.83346 \dots, 0.16616 \dots)

f (x) = \frac{8}{x ^{2} - 1}

P (x) = 2 x^{2} + 4 x - 16

f (x) = \frac{x}{x ^{2} + 49}

f (x) = lo g_{2} (2 x - \frac{1}{2})

f (x) = 2 x^{2} - 8 x + 16

What is the f(x)=(sqrt(x^2-9))/(x^2+2x-8) ?
The f(x)=(sqrt(x^2-9))/(x^2+2x-8) is