What is the inverse of 1/(1-\frac{1){x-2}} ?

The inverse of 1/(1-\frac{1){x-2}} is (-2+3x)/(x-1)

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inverse of 1/(1-\frac{1){x-2}}

inverse

\frac{1}{1 - \frac{1}{x - 2}}

\frac{- 2 + 3 x}{x - 1}

Solution steps

y = \frac{1}{1 - \frac{1}{x - 2}}

Replace

x

with

y

x = \frac{1}{1 - \frac{1}{y - 2}}

Solve for

y, x = \frac{1}{1 - \frac{1}{y - 2}}

\frac{- 2 + 3 x}{x - 1}

f (x) = \frac{x + 1}{x ^{2} - 4 x + 3}

f (x) = 1 + x^{2}

y = \frac{10 x + 1}{x + 1}

5^{x} + 3

f (x) = x^{\frac{1}{5}}

What is the inverse of 1/(1-\frac{1){x-2}} ?
The inverse of 1/(1-\frac{1){x-2}} is (-2+3x)/(x-1)