What is the f(z)=sqrt(z)(4(z-1)^2+1/(z^3)) ?

The f(z)=sqrt(z)(4(z-1)^2+1/(z^3)) is

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f(z)=sqrt(z)(4(z-1)^2+1/(z^3))

f (z) = z (4 (z - 1)^{2} + \frac{1}{z ^{3}})

Domain : z > 0

Range : f (z) \geq 0.80016 \dots

Intercepts : None

Asymptotes : Vertical z = 0

Extreme Points : Minimum (1.16427 \dots, 0.80016 \dots)

Interval Notation

Domain : (0, \infty)

Range : [0.80016 \dots, \infty)

Solution steps

Domain of

z (4 (z - 1)^{2} + \frac{1}{z ^{3}}) : z > 0

Range of

z (4 (z - 1)^{2} + \frac{1}{z ^{3}}) : f (z) \geq 0.80016 \dots

Axis interception points of

z (4 (z - 1)^{2} + \frac{1}{z ^{3}}) :

None

Asymptotes of

z (4 (z - 1)^{2} + \frac{1}{z ^{3}}) :

Vertical

: z = 0

Extreme Points of

z (4 (z - 1)^{2} + \frac{1}{z ^{3}}) :

Minimum

(1.16427 \dots, 0.80016 \dots)

p (t) = 10 (1.05)^{t}

f (t) = t^{2} + 2 t^{4} + 1

f (x) = 5 x^{2} x + 1

y = - 2 x^{2} - 5

y = - x^{3} - 5 x^{2} - 3 x + 9

What is the f(z)=sqrt(z)(4(z-1)^2+1/(z^3)) ?
The f(z)=sqrt(z)(4(z-1)^2+1/(z^3)) is