What is the inverse of f(x)=\sqrt[3]{(x+3)/2} ?

The inverse of f(x)=\sqrt[3]{(x+3)/2} is 2x^3-3

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inverse of f(x)=\sqrt[3]{(x+3)/2}

inverse

2 x^{3} - 3

Solution steps

Replace

x

with

y

Solve for

2 x^{3} - 3

f (x) = \frac{x ^{2} - 4}{x - 3}

f (x) = (x - 4)^{\frac{2}{3}}

f (x) = \frac{x ^{2} - 4 x + 4}{x ^{3} - 5 x ^{2}}

f (x) = 2 cos (π x - 4) + 2

\frac{1}{2} x^{4} - x^{3} - 36 x^{2} + 108 x + 80

What is the inverse of f(x)=\sqrt[3]{(x+3)/2} ?
The inverse of f(x)=\sqrt[3]{(x+3)/2} is 2x^3-3