What is the domain of f(x)=(5(x^2-1))/(x^2-4) ?

The domain of f(x)=(5(x^2-1))/(x^2-4) is x 2

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domain of f(x)=(5(x^2-1))/(x^2-4)

domain

f (x) = \frac{5 ( x ^{2} - 1 )}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = \frac{( 8 x - 5 )}{8 x}

y = \frac{3}{4} x - 8

(\frac{1}{9}) x - (\frac{1}{7}) y = 1

\frac{2 x ^{3} + 3}{x ^{3} - 1}

What is the domain of f(x)=(5(x^2-1))/(x^2-4) ?
The domain of f(x)=(5(x^2-1))/(x^2-4) is x<-2\lor-2<x<2\lor x>2