What is the domain of f(x)=sqrt(6x-3) ?

The domain of f(x)=sqrt(6x-3) is x>= 1/2

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domain of f(x)=sqrt(6x-3)

domain

f (x) = 6 x - 3

x \geq \frac{1}{2}

Interval Notation

[\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

The function domain

x \geq \frac{1}{2}

f (x) = \frac{x}{x ^{2} - 4}

(2, 1), (8, 7)

f (x) = (7 - 8 t)^{\frac{7}{2}}

f (x) = \frac{x ^{2} ( x + 4 )}{( 7 x ^{2} - 3 )}

y = - 3 x^{2} + 30 x - 2

What is the domain of f(x)=sqrt(6x-3) ?
The domain of f(x)=sqrt(6x-3) is x>= 1/2