What is the f(x)=(x^4-1)/(x^2-1) ?

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f(x)=(x^4-1)/(x^2-1)

f (x) = \frac{x ^{4} - 1}{x ^{2} - 1}

Domain : x < - 1 or - 1 < x < 1 or x > 1

Range : 1 \leq f (x) < 2 or f (x) > 2

Y Intercepts : (0, 1)

Asymptotes : None

Extreme Points : Minimum (0, 1)

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Range : [1, 2) \cup (2, \infty)

Solution steps

Domain of

\frac{x ^{4} - 1}{x ^{2} - 1} : x < - 1 or - 1 < x < 1 or x > 1

Range of

\frac{x ^{4} - 1}{x ^{2} - 1} : 1 \leq f (x) < 2 or f (x) > 2

Axis interception points of

\frac{x ^{4} - 1}{x ^{2} - 1} :

Y Intercepts

: (0, 1)

Asymptotes of

\frac{x ^{4} - 1}{x ^{2} - 1} :

None

Extreme Points of

\frac{x ^{4} - 1}{x ^{2} - 1} :

Minimum

(0, 1)

f (x) = {2 x - 1 : - 3 < x \leq 0, x + 1 : 0 < x \leq 8}

f (x) = cos (6 x) - 3 sin (3 x) + 1

f (x) = x^{3} + 4 x^{2} + 2

f (x) = \frac{x ^{2} + 2 x}{1} + \frac{3 x - x ^{2}}{2 x}