What is the y=(10)/(sqrt(x^2-4x+1)) ?

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y=(10)/(sqrt(x^2-4x+1))

y = \frac{10}{x ^{2} - 4 x + 1}

Domain : x < 2 - 3 or x > 2 + 3

Range : f (x) > 0

Y Intercepts : (0, 10)

Asymptotes : Vertical x = 2 - 3, x = 2 + 3, Horizontal y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, 2 - 3) \cup (2 + 3, \infty)

Range : (0, \infty)

Solution steps

Domain of

\frac{10}{x ^{2} - 4 x + 1} : x < 2 - 3 or x > 2 + 3

Range of

\frac{10}{x ^{2} - 4 x + 1} : f (x) > 0

Axis interception points of

\frac{10}{x ^{2} - 4 x + 1} :

Y Intercepts

: (0, 10)

Asymptotes of

\frac{10}{x ^{2} - 4 x + 1} :

Vertical

: x = 2 - 3, x = 2 + 3,

Horizontal

: y = 0

Extreme Points of

\frac{10}{x ^{2} - 4 x + 1} :

None

y = \frac{1}{2} (x + 2)^{2} - 4

y = \frac{1}{2} (x + 2)^{2} + 2

f (s) = \frac{s ^{3} + 3 s ^{2} - s + 1}{4 s ^{4} - 2 s ^{3} + s ^{2} - s + 2}

f (x_{- 2}) = x_{- 2}

f (x) = e^{x} cos (x) d x