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Popular >

range of-x^2+2x-6

Solution

range

- x^{2} + 2 x - 6

Solution

f (x) \leq - 5

+1

Interval Notation

(- \infty, - 5]

Solution steps

Vertex of

- x^{2} + 2 x - 6 :

Maximum

(1, - 5)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (1, - 5)

f (x) \leq - 5

Popular Examples

slope ofintercept y=-2/5 x+8 slope intercept

y = - \frac{2}{5} x + 8

vertices y=x^2-6x+7 vertices

y = x^{2} - 6 x + 7

critical (x^3)/(x^2-1)critical points

\frac{x ^{3}}{x ^{2} - 1}

range of f(x)=|x-2|range

f (x) = ∣ x - 2 ∣

intercepts of x^3-4x^2+8x-5 intercepts

x^{3} - 4 x^{2} + 8 x - 5

Frequently Asked Questions (FAQ)

What is the range of-x^2+2x-6 ?
The range of-x^2+2x-6 is f(x)<=-5