What is the domain of f(x)=e^{sqrt(x^3-6x^2+8x)} ?

The domain of f(x)=e^{sqrt(x^3-6x^2+8x)} is 0 = 4

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domain of f(x)=e^{sqrt(x^3-6x^2+8x)}

domain

f (x) = e^{x^{3} - 6 x^{2} + 8 x}

0 \leq x \leq 2 or x \geq 4

Interval Notation

[0, 2] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 2 or x \geq 4

The function domain

0 \leq x \leq 2 or x \geq 4

(8, - 4), (12, 2)

f (x) = 3 x y - 2 x - 4 y - 3 = 0

cos^{2} (x) + 2

- \frac{17}{13}

2 x^{2} + 4 x - 1

What is the domain of f(x)=e^{sqrt(x^3-6x^2+8x)} ?
The domain of f(x)=e^{sqrt(x^3-6x^2+8x)} is 0<= x<= 2\lor x>= 4