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Popular >

h(x)=160x-16x^2

Solution

h (x) = 160 x - 16 x^{2}

Solution

Domain : - \infty < x < \infty

Range : f (x) \leq 400

X Intercepts : (0, 0), (10, 0), Y Intercepts : (0, 0)

Vertex : Maximum (5, 400)

Inverse : - \frac{- 20 + - x + 400}{4}, \frac{- x + 400 + 20}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Solution steps

Domain of

160 x - 16 x^{2} : - \infty < x < \infty

Range of

160 x - 16 x^{2} : f (x) \leq 400

Axis interception points of

160 x - 16 x^{2} :

X Intercepts

: (0, 0), (10, 0),

Y Intercepts

: (0, 0)

Vertex of

160 x - 16 x^{2} :

Maximum

(5, 400)

Inverse of

160 x - 16 x^{2} : - \frac{- 20 + - x + 400}{4}, \frac{- x + 400 + 20}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the h(x)=160x-16x^2 ?
The h(x)=160x-16x^2 is