What is the inverse of f(x)=-3(x-1)^2+2 ?

The inverse of f(x)=-3(x-1)^2+2 is sqrt(-(x-2)/3)+1,-sqrt(-(x-2)/3)+1

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inverse of f(x)=-3(x-1)^2+2

inverse

f (x) = - 3 (x - 1)^{2} + 2

- \frac{x - 2}{3} + 1, - - \frac{x - 2}{3} + 1

Solution steps

y = - 3 (x - 1)^{2} + 2

Replace

x

with

y

x = - 3 (y - 1)^{2} + 2

Solve for

y, x = - 3 (y - 1)^{2} + 2

- \frac{x - 2}{3} + 1, - - \frac{x - 2}{3} + 1

f (x) = \frac{1}{2} (x - 4)^{2} + 1

f (x) = \frac{7 - 3 x}{2 x - 3}

f (x) = \frac{2 x - 3}{3 x - 1}

f (x) = \frac{3 - 2 x}{2 x - 5}

f (x) = \frac{x ^{2}}{1 + x ^{2}}

What is the inverse of f(x)=-3(x-1)^2+2 ?
The inverse of f(x)=-3(x-1)^2+2 is sqrt(-(x-2)/3)+1,-sqrt(-(x-2)/3)+1