What is the inverse of f(x)=2x^2+7x-3 ?

The inverse of f(x)=2x^2+7x-3 is (-7+sqrt(8x+73))/4 ,(-7-sqrt(8x+73))/4

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inverse of f(x)=2x^2+7x-3

inverse

f (x) = 2 x^{2} + 7 x - 3

\frac{- 7 + 8 x + 73}{4}, \frac{- 7 - 8 x + 73}{4}

Solution steps

y = 2 x^{2} + 7 x - 3

Replace

x

with

y

x = 2 y^{2} + 7 y - 3

Solve for

y, x = 2 y^{2} + 7 y - 3

\frac{- 7 + 8 x + 73}{4}, \frac{- 7 - 8 x + 73}{4}

f (x) = 2^{x - 3} - 5

f (x) = 2 π r^{2} + 8 π r

f (x) = 2 (3 x + 1) + 4

f (x) = \frac{x}{x - 3}

f (x) = \frac{1}{4} (x + 3)^{2} - 2

What is the inverse of f(x)=2x^2+7x-3 ?
The inverse of f(x)=2x^2+7x-3 is (-7+sqrt(8x+73))/4 ,(-7-sqrt(8x+73))/4