What is the inverse of f(x)=(x-5)^2-4 ?

The inverse of f(x)=(x-5)^2-4 is sqrt(x+4)+5,-sqrt(x+4)+5

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inverse of f(x)=(x-5)^2-4

inverse

f (x) = (x - 5)^{2} - 4

x + 4 + 5, - x + 4 + 5

Solution steps

y = (x - 5)^{2} - 4

Replace

x

with

y

x = (y - 5)^{2} - 4

Solve for

y, x = (y - 5)^{2} - 4

x + 4 + 5, - x + 4 + 5

f (x) = \frac{1}{3} (x - 4)^{2} + 2

f (x) = - 15 x^{2} + 350 x - 2000

f (x) = - 5 x + 4 + 3

2 π r^{2} + 12 π r

f (x) = \frac{x + 2}{- 2 x + 1}

What is the inverse of f(x)=(x-5)^2-4 ?
The inverse of f(x)=(x-5)^2-4 is sqrt(x+4)+5,-sqrt(x+4)+5