What is the inverse of f(x)=ln(x^2-4)+pi ?

The inverse of f(x)=ln(x^2-4)+pi is sqrt(e^{x-pi)+4},-sqrt(e^{x-pi)+4}

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inverse of f(x)=ln(x^2-4)+pi

inverse

f (x) = ln (x^{2} - 4) + π

e^{x - π} + 4, - e^{x - π} + 4

Solution steps

y = ln (x^{2} - 4) + π

Replace

x

with

y

x = ln (y^{2} - 4) + π

Solve for

y, x = ln (y^{2} - 4) + π

e^{x - π} + 4, - e^{x - π} + 4

\frac{3 x - 4}{2 - x}

\frac{5 - 3 x}{2 x - 3}

f (x) = 0.2 x + 5.3

f (x) = (2 x + 17)^{2}

f (x) = \frac{1}{x + 5} - 1

What is the inverse of f(x)=ln(x^2-4)+pi ?
The inverse of f(x)=ln(x^2-4)+pi is sqrt(e^{x-pi)+4},-sqrt(e^{x-pi)+4}