What is the inverse of f(x)=(2x+17)^2 ?

The inverse of f(x)=(2x+17)^2 is (sqrt(x)-17)/2 ,(-sqrt(x)-17)/2

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inverse of f(x)=(2x+17)^2

inverse

f (x) = (2 x + 17)^{2}

\frac{x - 17}{2}, \frac{- x - 17}{2}

Solution steps

y = (2 x + 17)^{2}

Replace

x

with

y

x = (2 y + 17)^{2}

Solve for

y, x = (2 y + 17)^{2}

\frac{x - 17}{2}, \frac{- x - 17}{2}

f (x) = \frac{1}{x + 5} - 1

\frac{t + 2}{t ^{2} + 5 t + 6}

f (x) = x^{2} - 8 x + 40

f (x) = \frac{3 x + 2}{2 - x}

f (x) = 2 3 x + 1 + 4

What is the inverse of f(x)=(2x+17)^2 ?
The inverse of f(x)=(2x+17)^2 is (sqrt(x)-17)/2 ,(-sqrt(x)-17)/2