What is the inverse of 3+sqrt(x^2-4) ?

The inverse of 3+sqrt(x^2-4) is sqrt(x^2-6x+13),-sqrt(x^2-6x+13)

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inverse of 3+sqrt(x^2-4)

inverse

3 + x^{2} - 4

x^{2} - 6 x + 13, - x^{2} - 6 x + 13

Solution steps

y = 3 + x^{2} - 4

Replace

x

with

y

x = 3 + y^{2} - 4

Solve for

y, x = 3 + y^{2} - 4

x^{2} - 6 x + 13, - x^{2} - 6 x + 13

f (x) = 5 x + 18

f (x) = \frac{2}{x + 1} - 5

y = (x - 5)^{2} - 4

f (x) = 3 x^{2} + 18 x - 10

f (x) = \frac{3}{2} x + 5

What is the inverse of 3+sqrt(x^2-4) ?
The inverse of 3+sqrt(x^2-4) is sqrt(x^2-6x+13),-sqrt(x^2-6x+13)