What is the inverse of f(x)=3x^2+18x-10 ?

The inverse of f(x)=3x^2+18x-10 is (-18+sqrt(12x+444))/6 ,(-18-sqrt(12x+444))/6

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inverse of f(x)=3x^2+18x-10

inverse

f (x) = 3 x^{2} + 18 x - 10

\frac{- 18 + 12 x + 444}{6}, \frac{- 18 - 12 x + 444}{6}

Solution steps

y = 3 x^{2} + 18 x - 10

Replace

x

with

y

x = 3 y^{2} + 18 y - 10

Solve for

y, x = 3 y^{2} + 18 y - 10

\frac{- 18 + 12 x + 444}{6}, \frac{- 18 - 12 x + 444}{6}

f (x) = \frac{3}{2} x + 5

- 4 - 2 x + 1 - 2

f (x) = - 7 (x + 2)^{2} - 4

y = 6 - lo g_{5} (2 x - 7)

\frac{t - 5}{3 t - 18}

What is the inverse of f(x)=3x^2+18x-10 ?
The inverse of f(x)=3x^2+18x-10 is (-18+sqrt(12x+444))/6 ,(-18-sqrt(12x+444))/6