What is the inverse of f(x)=-7(x+2)^2-4 ?

The inverse of f(x)=-7(x+2)^2-4 is sqrt(-(x+4)/7)-2,-sqrt(-(x+4)/7)-2

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inverse of f(x)=-7(x+2)^2-4

inverse

f (x) = - 7 (x + 2)^{2} - 4

- \frac{x + 4}{7} - 2, - - \frac{x + 4}{7} - 2

Solution steps

y = - 7 (x + 2)^{2} - 4

Replace

x

with

y

x = - 7 (y + 2)^{2} - 4

Solve for

y, x = - 7 (y + 2)^{2} - 4

- \frac{x + 4}{7} - 2, - - \frac{x + 4}{7} - 2

y = 6 - lo g_{5} (2 x - 7)

\frac{t - 5}{3 t - 18}

f (x) = 12 - (7 x + 9)^{5}

2 X - 3

What is the inverse of f(x)=-7(x+2)^2-4 ?
The inverse of f(x)=-7(x+2)^2-4 is sqrt(-(x+4)/7)-2,-sqrt(-(x+4)/7)-2