What is the inverse of sqrt(1-\sqrt{4-x^2)} ?

The inverse of sqrt(1-\sqrt{4-x^2)} is sqrt(-x^4+2x^2+3),-sqrt(-x^4+2x^2+3)

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inverse of sqrt(1-\sqrt{4-x^2)}

inverse

1 - 4 - x^{2}

- x^{4} + 2 x^{2} + 3, - - x^{4} + 2 x^{2} + 3

Solution steps

y = 1 - 4 - x^{2}

Replace

x

with

y

x = 1 - 4 - y^{2}

Solve for

y, x = 1 - 4 - y^{2}

- x^{4} + 2 x^{2} + 3, - - x^{4} + 2 x^{2} + 3

y = - 3 x + 6

f (x) = ln (x + 1) - 2

f (x) = (x + 3)^{4}

ln (x^{2} - 2 x)

e^{x^{2} - 2 x}

What is the inverse of sqrt(1-\sqrt{4-x^2)} ?
The inverse of sqrt(1-\sqrt{4-x^2)} is sqrt(-x^4+2x^2+3),-sqrt(-x^4+2x^2+3)