What is the inverse of sqrt((3-12x)/(6+4x)) ?

The inverse of sqrt((3-12x)/(6+4x)) is (3-6x^2)/(4(x^2+3))

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inverse of sqrt((3-12x)/(6+4x))

inverse

\frac{3 - 12 x}{6 + 4 x}

\frac{3 - 6 x ^{2}}{4 ( x ^{2} + 3 )}

Solution steps

y = \frac{3 - 12 x}{6 + 4 x}

Replace

x

with

y

x = \frac{3 - 12 y}{6 + 4 y}

Solve for

y, x = \frac{3 - 12 y}{6 + 4 y}

\frac{3 - 6 x ^{2}}{4 ( x ^{2} + 3 )}

f (x) = e^{- (x - 2)} - 1

\frac{3 + x ^{4}}{x ^{2} + x ^{4}}

f (x) = x^{\frac{1}{3}} - 1

\frac{1}{( x + 4 ) ^{2}} - 5

What is the inverse of sqrt((3-12x)/(6+4x)) ?
The inverse of sqrt((3-12x)/(6+4x)) is (3-6x^2)/(4(x^2+3))