What is the inverse of (2x^2-22x+48)/(2x^2-25x+72) ?

The inverse of (2x^2-22x+48)/(2x^2-25x+72) is (-6+9x)/(2(-1+x))

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inverse of (2x^2-22x+48)/(2x^2-25x+72)

inverse

\frac{2 x ^{2} - 22 x + 48}{2 x ^{2} - 25 x + 72}

\frac{- 6 + 9 x}{2 ( - 1 + x )}

Solution steps

y = \frac{2 x ^{2} - 22 x + 48}{2 x ^{2} - 25 x + 72}

Replace

x

with

y

x = \frac{2 y ^{2} - 22 y + 48}{2 y ^{2} - 25 y + 72}

Solve for

y, x = \frac{2 y ^{2} - 22 y + 48}{2 y ^{2} - 25 y + 72}

\frac{- 6 + 9 x}{2 ( - 1 + x )}

(x - 8)^{3}

f (x) = \frac{( x + 5 )}{( 2 x + 1 )}

f (x) = \frac{2 x}{3} + \frac{3}{5}

\frac{x}{x ^{2} - 9}

f (x) = \frac{4 x + 2}{x - 3}

What is the inverse of (2x^2-22x+48)/(2x^2-25x+72) ?
The inverse of (2x^2-22x+48)/(2x^2-25x+72) is (-6+9x)/(2(-1+x))