What is the inverse of f(x)=x^2-4,x<-2 ?

The inverse of f(x)=x^2-4,x<-2 is sqrt(x+4),-sqrt(x+4)

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inverse of f(x)=x^2-4,x<-2

inverse

f (x) = x^{2} - 4, x < - 2

x + 4, - x + 4

Solution steps

y = x^{2} - 4

Replace

x

with

y

x = y^{2} - 4

Solve for

y, x = y^{2} - 4

x + 4, - x + 4

\frac{x + 1}{x ^{2} - 5 x + 6}

sin (x^{3} + 1)

f (x) = lo g_{3} (4 x + 5) - 6

f (x) = 2 π r

\frac{2 x ^{2} - 2}{x ^{2} + 3 x - 4}

What is the inverse of f(x)=x^2-4,x<-2 ?
The inverse of f(x)=x^2-4,x<-2 is sqrt(x+4),-sqrt(x+4)