What is the inverse of f(x)=2(x-8)^2+5 ?

The inverse of f(x)=2(x-8)^2+5 is sqrt((x-5)/2)+8,-sqrt((x-5)/2)+8

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inverse of f(x)=2(x-8)^2+5

inverse

f (x) = 2 (x - 8)^{2} + 5

\frac{x - 5}{2} + 8, - \frac{x - 5}{2} + 8

Solution steps

y = 2 (x - 8)^{2} + 5

Replace

x

with

y

x = 2 (y - 8)^{2} + 5

Solve for

y, x = 2 (y - 8)^{2} + 5

\frac{x - 5}{2} + 8, - \frac{x - 5}{2} + 8

f (x) = \frac{5 - 2 x}{( 4 x - 2 )}

2 x^{2} + 7 x - 3

f (x) = - 3 x + 2 - 6, x \geq - 2

f (x) = 6 x + 8 - 5

f (x) = 2 (x - 2)^{2} = 8 (7 + y)

What is the inverse of f(x)=2(x-8)^2+5 ?
The inverse of f(x)=2(x-8)^2+5 is sqrt((x-5)/2)+8,-sqrt((x-5)/2)+8