What is the inverse of f(x)= 2/(sqrt(x^3+27)) ?

The inverse of f(x)= 2/(sqrt(x^3+27)) is cube root of (4-27x^2)/(x^2)

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inverse of f(x)= 2/(sqrt(x^3+27))

inverse

f (x) = \frac{2}{x ^{3} + 27}

Solution steps

y = \frac{2}{x ^{3} + 27}

Replace

x

with

y

x = \frac{2}{y ^{3} + 27}

Solve for

y, x = \frac{2}{y ^{3} + 27}

2 π r^{2} + 16 π r

f (x) = 4 (x - 12) + 2

f (x) = \frac{x}{3} - 9

\frac{7 - 3 x}{2 x - 3}

y = 2 (3^{x}) + 1

What is the inverse of f(x)= 2/(sqrt(x^3+27)) ?
The inverse of f(x)= 2/(sqrt(x^3+27)) is cube root of (4-27x^2)/(x^2)