What is the inverse of f(x)=-(x+1)^2-1 ?

The inverse of f(x)=-(x+1)^2-1 is sqrt(-x-1)-1,-sqrt(-x-1)-1

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inverse of f(x)=-(x+1)^2-1

inverse

f (x) = - (x + 1)^{2} - 1

- x - 1 - 1, - - x - 1 - 1

Solution steps

y = - (x + 1)^{2} - 1

Replace

x

with

y

x = - (y + 1)^{2} - 1

Solve for

y, x = - (y + 1)^{2} - 1

- x - 1 - 1, - - x - 1 - 1

f (x) = - \frac{1}{4} x + 2

f (x) = x^{2} + 4, x \leq 0

x^{3} + 5

f (x) = 2 x^{2} - 20 x + 58

3 ln (x + 5) - 2

What is the inverse of f(x)=-(x+1)^2-1 ?
The inverse of f(x)=-(x+1)^2-1 is sqrt(-x-1)-1,-sqrt(-x-1)-1