What is the inverse of f(x)=0.5(x-6)^2-3 ?

The inverse of f(x)=0.5(x-6)^2-3 is sqrt(2)sqrt(x+3)+6,-sqrt(2)sqrt(x+3)+6

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inverse of f(x)=0.5(x-6)^2-3

inverse

f (x) = 0.5 (x - 6)^{2} - 3

2 x + 3 + 6, - 2 x + 3 + 6

Solution steps

y = 0.5 (x - 6)^{2} - 3

Replace

x

with

y

x = 0.5 (y - 6)^{2} - 3

Solve for

y, x = 0.5 (y - 6)^{2} - 3

2 x + 3 + 6, - 2 x + 3 + 6

\frac{5 x + 2}{14 x ^{2}}

f (x) = \frac{1}{x} - x

f (x) = \frac{3 x - 4}{3 - x}

f (x) = 3 (x + 2)^{2} + 1

f (x) = x^{2} + 8 x + 16

What is the inverse of f(x)=0.5(x-6)^2-3 ?
The inverse of f(x)=0.5(x-6)^2-3 is sqrt(2)sqrt(x+3)+6,-sqrt(2)sqrt(x+3)+6