What is the inverse of f(x)=x^2-3x+4 ?

The inverse of f(x)=x^2-3x+4 is (3+sqrt(4x-7))/2 ,(3-sqrt(4x-7))/2

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inverse of f(x)=x^2-3x+4

inverse

f (x) = x^{2} - 3 x + 4

\frac{3 + 4 x - 7}{2}, \frac{3 - 4 x - 7}{2}

Solution steps

y = x^{2} - 3 x + 4

Replace

x

with

y

x = y^{2} - 3 y + 4

Solve for

y, x = y^{2} - 3 y + 4

\frac{3 + 4 x - 7}{2}, \frac{3 - 4 x - 7}{2}

f (x) = \frac{1 - x}{x - 2}

f (x) = 5^{x} - 5^{- x}

f (x) = 4 x + 5 (x - 3)

f (x) = 0.4 x + 5.7

y = 3 (2^{4 x - 5})

What is the inverse of f(x)=x^2-3x+4 ?
The inverse of f(x)=x^2-3x+4 is (3+sqrt(4x-7))/2 ,(3-sqrt(4x-7))/2