What is the inverse of f(x)=5x^2+6,x>= 0 ?

The inverse of f(x)=5x^2+6,x>= 0 is sqrt((x-6)/5),-sqrt((x-6)/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=5x^2+6,x>= 0

inverse

f (x) = 5 x^{2} + 6, x \geq 0

\frac{x - 6}{5}, - \frac{x - 6}{5}

Solution steps

y = 5 x^{2} + 6

Replace

x

with

y

x = 5 y^{2} + 6

Solve for

y, x = 5 y^{2} + 6

\frac{x - 6}{5}, - \frac{x - 6}{5}

+ x^{2} + 3 x - 4

f (x) = ln (x) + 1

f (x) = 5 + 4 x - 4

\frac{2 x ^{2} + 4 x}{2 x + 2}

f (x) = lo g_{9} (x) + lo g_{9} (12)

What is the inverse of f(x)=5x^2+6,x>= 0 ?
The inverse of f(x)=5x^2+6,x>= 0 is sqrt((x-6)/5),-sqrt((x-6)/5)