What is the inverse of f(x)=(x+1)/(2(x-1)) ?

The inverse of f(x)=(x+1)/(2(x-1)) is (1+2x)/(2x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x+1)/(2(x-1))

inverse

f (x) = \frac{x + 1}{2 ( x - 1 )}

\frac{1 + 2 x}{2 x - 1}

Solution steps

y = \frac{x + 1}{2 ( x - 1 )}

Replace

x

with

y

x = \frac{y + 1}{2 ( y - 1 )}

Solve for

y, x = \frac{y + 1}{2 ( y - 1 )}

\frac{1 + 2 x}{2 x - 1}

f (x) = \frac{x + 5}{x + 8}

f (x) = \frac{3 x - 7}{x + 9}

f (x) = 2 - 4 x

f (x) = 0.05 x + 25

f (x) = - 2 (x + 5)^{2} - 2

What is the inverse of f(x)=(x+1)/(2(x-1)) ?
The inverse of f(x)=(x+1)/(2(x-1)) is (1+2x)/(2x-1)