What is the inverse of f(x)= 3/(sqrt(9-x^2)) ?

The inverse of f(x)= 3/(sqrt(9-x^2)) is sqrt(-(9-9x^2)/(x^2)),-sqrt(-(9-9x^2)/(x^2))

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inverse of f(x)= 3/(sqrt(9-x^2))

inverse

f (x) = \frac{3}{9 - x ^{2}}

- \frac{9 - 9 x ^{2}}{x ^{2}}, - - \frac{9 - 9 x ^{2}}{x ^{2}}

Solution steps

y = \frac{3}{9 - x ^{2}}

Replace

x

with

y

x = \frac{3}{9 - y ^{2}}

Solve for

y, x = \frac{3}{9 - y ^{2}}

- \frac{9 - 9 x ^{2}}{x ^{2}}, - - \frac{9 - 9 x ^{2}}{x ^{2}}

f (x) = x^{2} + 4 x - 6

f (x) = \frac{x}{( 1 + 2 x )}

f (x) = (3 x - 1)^{5}

f (x) = \frac{2 x + 3}{x - 1} = 5

What is the inverse of f(x)= 3/(sqrt(9-x^2)) ?
The inverse of f(x)= 3/(sqrt(9-x^2)) is sqrt(-(9-9x^2)/(x^2)),-sqrt(-(9-9x^2)/(x^2))